A particle of mass m_1 is moving with a velocity v_1 and another … - Vidyadip

MCQ

A particle of mass ${m_1}$ is moving with a velocity ${v_1}$and another particle of mass ${m_2}$is moving with a velocity ${v_2}$. Both of them have the same momentum but their different kinetic energies are ${E_1}$and ${E_2}$respectively. If ${m_1} > {m_2}$ then

✓
${E_1} < {E_2}$
B
$\frac{{{E_1}}}{{{E_2}}} = \frac{{{m_1}}}{{{m_2}}}$
C
${E_1} > {E_2}$
D
${E_1} = {E_2}$

✓

Answer

Correct option: A.

${E_1} < {E_2}$

a
(a)$E = \frac{{{P^2}}}{{2m}}$ if $P =$ constant then $E \propto \frac{1}{m}$
According to problem ${m_1} > {m_2} \,\therefore \, {E_1} < {E_2}$

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