A bullet of mass 4,g is fired horizontally with a speed of 300,m/s into 0.8,kg block of wood at rest on a table. If the

Q: A bullet of mass $4\,g$ is fired horizontally with a speed of $300\,m/s$ into $0.8\,kg$ block of wood at rest on a table. If the coefficient of friction between the block and the table is $0.3,$ how far will the block slide approximately?

b $\begin{array}{l} Given,\,{m_1} = 4g,{u_1} = 300m/s\\ {m_2} = 0.8\,kg = 800\,g,\,{u_2} = 0\,m/s\\ From\,law\,of\,conservation\,of\,momentum,\\ {m_1}{u_1} + {m_2}{u_2} = {m_1}{v_1} + {m_2}{v_2}\\ Let\,the\,velocity\,of\,combined\,system\\ = v\,m/s\\ then,\\ 4 \times 300 + 800 \times 0 = \left( {800 + 4} \right) \times v\\ v = \frac{{1200}}{{804}} = 1.49\,m/s \end{array}$ $\begin{array}{l} Now,\,\mu = 0.3\left( {given} \right)\\ a = \mu g\\ a = 0.3 \times 10\left( {take\,g = 10\,m/{s^2}} \right)\\ = 3\,m/{s^2}\\ then,\,from\,{v^2} = {u^2} + 2as\\ {\left( {1.49} \right)^2} = 0 + 2 \times 3 \times s\\ s = \frac{{\left( {{{1.49}^2}} \right)}}{6}\,;\,\,s = \frac{{2.22}}{6} = 0.379\,m \end{array}$

SECTION - A [PHYSICS - MCQ]

GSEB - English Medium

A bullet of mass $4\,g$ is fired horizontally with a speed of $300\,m/s$ into $0.8\,kg$ block of wood at rest on a table. If the coefficient of friction between the block and the table is $0.3,$ how far will the block slide approximately?

A$0.19\,m$
B$0.379\,m$
C$0.569\,m$
D$0.758\,m$

JEE MAIN 2014, Diffcult

STD 11 Science
NEET
STD 11 - 4.2. friction
Physics

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