A plastic disc of radius $R$ has a charge $q$ uniformly distributed over its surface. If the disc is rotated at an angular frequency $\omega$ about it axis, the induction at the center of the disc is :-
Diffcult
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$\frac{\mu_{0} \omega q}{2 \pi R}$ (Hint : Divide disc into rings, consider one such ring of radius $\mathrm{x}$, thickness $\mathrm{dx}.$ Then field at its center $\mathrm{dB}=\left(\mu_{0} \omega \mathrm{q} / 2\right)$ $\mathrm{dx}$ integrate to find $\mathrm{B}$ ).
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