A platinum resistance thermometer has a resistance of $50\,\Omega $ at $20\,^o C$. When dipped in a liquid the resistance becomes $76.8\,\Omega $. The temperature coefficient of resistance for platinum is $\alpha = 3.92 \times {10^{ - 3}}\,^o C$. The temperature of the liquid is .............. $^o C$
Medium
Download our app for free and get started
$\frac{{{R_1}}}{{{R_2}}} = \frac{{(1 + \alpha {t_1})}}{{(1 + \alpha {t_2})}} \Rightarrow \frac{{50}}{{76.8}} = \frac{{(1 + 3.92 \times {{10}^{ - 3}} \times 20)}}{{(1 + 3.92 \times {{10}^{ - 3}}t)}}$
$ \Rightarrow t = 167\,^o C$
Download our appand get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
Similar Questions
- 1Two resistors of resistance ${R_1}$ and ${R_2}$ having ${R_1} > {R_2}$ are connected in parallel. For equivalent resistance $R$, the correct statement isView Solution
- 2A potentiometer circuit is set up as shown. The potential gradient, across the potentiometer wire, is $k$ $volt/cm$ and the ammeter, present in the circuit, reads $1.0\,\, A$ when two way key is switched off. The balance points, when the key between the terminals $(i)$ $1$ and $2$ $(ii)$ $1$ and $3,$ is plugged in, are found to be at lengths $l_1$ and $l_2$ respectively. The magnitudes, of the resistors $R$ and $X,$ in $ohms$, are then, equal, respectively, toView Solution
- 3In the following circuit, $5$ $\Omega$ resistor develops $45$ $J/s$ due to current flowing through it. The power developed per second across $12$ $\Omega$ resistor is ............. $W$View Solution
- 4An unknown resistance $R_1$ is connected in series with a resistance of $10 \,\Omega$. This combinations is connected to one gap of a meter bridge while a resistance $R_2$ is connected in the other gap. The balance point is at $50\, cm$. Now, when the $10 \,\Omega$ resistance is removed the balance point shifts to $40\, cm$. The value of $R_1$ is (in $ohm$)View Solution
- 5With a potentiometer null point were obtained at $140\, cm$ and $180\, cm$ with cells of $emf$ $1.1 \,V$ and one unknown $X\, volts$. Unknown $emf$ is .............. $V$View Solution
- 6In the adjoining circuit diagram each resistance is of $10$ $\Omega$. The current in the arm $AD$ will beView Solution
- 7View SolutionThe reading of the ammeter as per figure shown is
- 8In the circuit element given here, if the potential at point $B$, $V_B = 0$, then the potentials of $A$ and $D$ are given asView Solution
- 9Five equal resistances each of resistance $R$ are connected as shown in the figure. A battery of $V\, volts$ is connected between $A$ and $B$. The current flowing in $AFCEB$ will beView Solution
- 10A constant electric current $I$ is passed through a straight conductor of length $l$. If $S$ in specific charge of electron then the total momentum of electrons isView Solution