A potentiometer having the potential gradient of 2, mV/cm is used to measure the difference of potential across a resistance of 10 ,Omega. If a

Q: A potentiometer having the potential gradient of $2\, mV/cm$ is used to measure the difference of potential across a resistance of $10 \,\Omega$. If a length of $50\, cm$ of the potentiometer wire is required to get the null point, the current passing through the $10 \,\Omega$ resistor is (in $mA$)

d (d) $V = xl \Rightarrow iR = xl$ $ \Rightarrow \,\,\,i \times 10 = \left( {\frac{{2 \times {{10}^{ - 3}}}}{{{{10}^{ - 2}}}}} \right) \times 50 \times {10^{ - 2}} = 0.1$ $ \Rightarrow \,\,\,\,i = 10 \times {10^{ - 3}}A = 10\,mA$.

SECTION - A [PHYSICS - MCQ]

GSEB - English Medium

A potentiometer having the potential gradient of $2\, mV/cm$ is used to measure the difference of potential across a resistance of $10 \,\Omega$. If a length of $50\, cm$ of the potentiometer wire is required to get the null point, the current passing through the $10 \,\Omega$ resistor is (in $mA$)

A$1$
B$2$
C$5$
D$10$

Medium

STD 11 Science
NEET
STD 12 - 3. current electricity
Physics

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