MCQ
A projectile cover double range as compare to its maximum height attained. The angle of projection is
- ✓$\tan^{-1} \,2$
- B$\tan^{-1} \,4$
- C$\tan^{-1} \,3$
- D$\tan^{-1} \,5$
✓
Answer
Correct option: A.
$\tan^{-1} \,2$
a
$\frac{\mathrm{h}}{\mathrm{R}}=\frac{\tan \theta}{4}$
$\frac{\mathrm{h}}{\mathrm{R}}=\frac{\tan \theta}{4}$
$\frac{1}{2}=\frac{\tan \theta}{4}$
$\tan \theta=2$
$\theta=\tan ^{-1} 2$
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