A proton has a mass $1.67 \times 10^{-27} \,kg$ and charge $+1.6 \times 10^{-19} \,C$. If the proton is accelerated through a potential difference of million volts, then the kinetic energy is ......... $J$
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(b)

$\left(1.6 \times 10^{-19}\right)\left(10^6\right)=\frac{1}{2}\left(1.67 \times 10^{-27}\right) v^2$

$1.6 \times 10^{-13}=\frac{1.67}{2} \times 10^{-27} v^2= KE$

$KE =1.6 \times 10^{-13} \,J$

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