A proton is accelerating in a cyclotron where the applied magnetic field is $2 \,T$. If the potential gap is effectively $100 \,kV$ then how much revolutions the proton has to make between the "dees" to acquire a kinetic energy of $20 \,MeV$ ?
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(a)
Energy increased in each revolution $=2 \times 100 \times 10^3 \,eV$
$=2 \times 10^5 \,eV$
Now for energy $E=2 \times 10^7 \,eV$
Number of revolution $=\frac{2 \times 10^7 \,eV }{2 \times 10^5 \,eV }=100$
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