A proton is moves on circular path with its constant angular speed then correct relation between its magnetic moment and angular momentum
A$\vec M = - \frac{{e\vec L}}{{2{m_p}}}$
B$\vec M = \frac{{e\vec L}}{{2{m_p}}}$
C$\vec M = \left( {\frac{{2e}}{{{m_p}}}} \right)\vec L$
D$\vec M = - \left( {\frac{{2e}}{{{m_p}}}} \right)\vec L$
Medium
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B$\vec M = \frac{{e\vec L}}{{2{m_p}}}$
b
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