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A proton of energy $200\, MeV$ enters the magnetic field of $5\, T$. If direction of field is from south to north and motion is upward, the force acting on it will be
  • A
    Zero
  • B$1.6 \times {10^{ - 10}}\,N$
  • C$3.2 \times {10^{ - 8}}\,N$
  • D$1.6 \times {10^{ - 6}}\,N$
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