A pump draws water from a tank which is at $2.5\; m$ down from outlet and issues it from the end of a hose which the water is drawn. The cross sectional area is $10\; cm ^{2}$, and the water leaves the end of the hose at a speed of $5\; m / s$. What is the rate at which the pump is working ?
$\frac{ dm }{ dt }= A \times V =10 \times 10^{-4} \times 10^{-3} \times 5=5 \;kg / s$
$=\left(9.8 \times 2.5+\frac{25}{2}\right)(5)$
$=185\; W$
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