A rectangular block of size $10\,cm \times 8\,cm \times 5\,cm$ is kept in three different positions $P, Q$ and $R$ in turn as shown in the figure. In each case, the shaded area is rigidly fixed and a definite force $F$ is applied tangentially to the opposite face to deform the block. The displacement of the upper face will be
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(d) $\eta = \frac{{F/A}}{{x/L}}$==> $x = \frac{L}{\eta } \times \frac{F}{A}$
If $\eta$ and $F$ are constant then $x \propto \frac{L}{A}$
For maximum displacement area at which force applied should be minimum and vertical side should be maximum, this is given in the $R$ position of rectangular block.
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