A river $10\,m$ deep is flowing at $5\,m/s$. The shearing stress between horizontal layers of the river is :- $(\eta = 10^{-3}\,SI\,unit)$
Medium
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Shear stress $=\frac{F_{11}}{A}=\frac{F_{\text {viscous }}}{A}=\eta \frac{\Delta V}{\Delta y}$
(Velocity gradient $\left.=\frac{\Delta \mathrm{V}}{\Delta \mathrm{y}}\right)$
Shear stress $=10^{-3} \times \frac{5}{10}=0.5 \times 10^{-3} \mathrm{N} / \mathrm{m}^{2}$
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