MCQ
A series whose $n^{th}$ term is $\left( {\frac{n}{x}} \right) + y,$ the sum of $r$ terms will be
  • $\left\{ {\frac{{r(r + 1)}}{{2x}}} \right\} + ry$
  • B
    $\left\{ {\frac{{r(r - 1)}}{{2x}}} \right\}$
  • C
    $\left\{ {\frac{{r(r - 1)}}{{2x}}} \right\} - ry$
  • D
    $\left\{ {\frac{{r(r + 1)}}{{2y}}} \right\} - rx$

Answer

Correct option: A.
$\left\{ {\frac{{r(r + 1)}}{{2x}}} \right\} + ry$
a
(a) On putting $n = 1,2,3,.....$

First term of the series $a = \frac{1}{x} + y$,

Second term =$\frac{2}{x} + y$

$d = \left( {\frac{2}{x} + y} \right) - \left( {\frac{1}{x} + y} \right) = \frac{1}{x}$

Sum of $r$ terms of the series

$ = \frac{r}{2}\left[ {2\left( {\frac{1}{x} + y} \right) + (r - 1)\frac{1}{x}} \right]$

$ = \frac{r}{2}\left[ {\frac{2}{x} + 2y + \frac{r}{x} - \frac{1}{x}} \right]$

$ = \frac{{{r^2} - r + 2r}}{{2x}} + ry$

$ = \left\{ {\frac{{r{\mkern 1mu} (r + 1)}}{{2x}}} \right\} + ry$.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free