.......$A$ should be the current in a circular coil of radius $5\,cm$ to annul ${B_H} = 5 \times {10^{ - 5}}\,T$
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(b) $B = {10^{ - 7}}\frac{{2\pi i}}{r}$; according to question $B_H = B$
$ \Rightarrow 5 \times {10^{ - 5}} = {10^{ - 7}} \times \frac{{2 \times 3.14 \times i}}{{5 \times {{10}^{ - 2}}}} \Rightarrow i = 4\,A$
$ \Rightarrow 5 \times {10^{ - 5}} = {10^{ - 7}} \times \frac{{2 \times 3.14 \times i}}{{5 \times {{10}^{ - 2}}}} \Rightarrow i = 4\,A$
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