d
Sound level decreases by $5\, dB$ every $km$ so sound level decreased in $20\, km =100 \,dB$
$\beta_{2}-\beta_{1}=10 \log _{10} \frac{ I _{2}}{ I _{1}}$
$-100=10 \log _{10} \frac{ I _{2}}{ I _{1}} \Rightarrow \frac{ I _{1}}{ I _{2}}=10^{10}$
$I _{2}=10^{-10} I _{1} \Rightarrow P _{2}=10^{-10} P _{1}=10^{-8}\, W$
$\mathrm { x } = 8$