Question
A solid cube and a solid sphere of the same material have equal surface area. Both are at the same temperature ${120^o}C$, then

Answer

(b)Rate of cooling of a body $R = \frac{{\Delta \theta }}{t} = \frac{{A\varepsilon \sigma ({T^4} - T_0^4)}}{{mc}}$
==> $R \propto \frac{A}{m} \propto \frac{{{\rm{Area}}}}{{{\rm{Volume}}}}$

==> For the same surface area. $R \propto \frac{1}{{{\rm{Volume}}}}$
( Volume of cube < Volume of sphere

==> ${R_{Cube}} > {R_{Sphere}}$ i.e. cube, cools down with faster rate.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

Two short magnets with their axes horizontal and perpendicular to the magnetic meridian are placed with their centres $40\, cm$  east and $ 50\,cm$  west of magnetic needle. If the needle remains undeflected, the ratio of their magnetic moments ${M_1}:{M_2}$ is
A body moves from rest with a constant acceleration of $5\,m/{s^2}$. Its instantaneous speed (in $m/s)$ at the end of $10\, sec$ is
Assume that an electric field $\vec E = 30{x^2}\hat i$ exists in space. Then the potential difference $V_A-V_O$ where $V_O$ is the potential at the origin and $V_A$ the potential at $x = 2\ m$ is....$V$
A circular loop of area $0.01\,{m^2}$ carrying a current of $10\, A$, is held perpendicular to a magnetic field of intensity $0.1\,T$. The torque acting on the loop is......$N-m$
Two identical photo-cathodes receive light of frequencies ${f_1}$ and ${f_2}$. If the velocities of the photo electrons (of mass $m$) coming out are respectively ${v_1}$ and ${v_2}$, then
In nuclear fission, the fission reactions proceeds with a projectile. Which of the following suits the best
Select the correct statement from the following
A man is standing in a lift which goes up and comes down with the same constant acceleration. If the ratio of the apparent weights in the two cases is $2 : 1$, then the acceleration of the lift is  ......... $m/s^2$
In the figure, a ladder of mass $m$ is shown leaning against a wall. It is in static equilibrium making an angle $\theta$ with the horizontal floor. The coefficient of friction between the wall and the ladder is $\mu_1$ and that between the floor and the ladder is $\mu_2$. The normal reaction of the wall on the ladder is $N_1$ and that of the floor is $N_2$. If the ladder is about to slip, then

$Image$

$(A)$ $\mu_1=0 \mu_2 \neq 0$ and $N _2 \tan \theta=\frac{ mg }{2}$

$(B)$ $\mu_1 \neq 0 \mu_2=0$ and $N_1 \tan \theta=\frac{m g}{2}$

$(C)$ $\mu_1 \neq 0 \mu_2 \neq 0$ and $N _2 \tan \theta=\frac{ mg }{1+\mu_1 \mu_2}$

$(D)$ $\mu_1=0 \mu_2 \neq 0$ and $N _1 \tan \theta=\frac{ mg }{2}$

Stars are not visible in the day time because