The temperature of hot and cold end of a $20cm$ long rod in thermal steady state are at ${100^o}C$ and ${20^o}C$ respectively. Temperature at the centre of the rod is...... $^oC$
A$50$
B$60$
C$40$
D$30$
Medium
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B$60$
b (b) Temperature gradient $ = \frac{{100 - 20}}{{20}} = 4^\circ C/cm$
temperature at centre $ = 100 - 4 \times 10$ = $ 60°C$
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