MCQ
A solution of $10\, ml$ $\frac{M}{{10}}FeS{O_4}$was titrated with $KMn{O_4}$ solution in acidic medium. The amount of $KMn{O_4}$ used will be
  • A
    $5\, ml $ of $0.1\, M$
  • B
    $10\, ml$ of $ 1.1\, M$
  • C
    $10\, ml $ of $0.5\, M$
  • $10\, ml$ of $0.02\, M$

Answer

Correct option: D.
$10\, ml$ of $0.02\, M$
d
(d)  $KMn{O_4}$                      $FeS{O_4}$

   $\frac{{{M_1}{V_1}}}{{{n_1}}}$ = $\frac{{{M_2}{V_2}}}{{{n_2}}}$;

${M_1}{V_1} = \frac{{{n_1}}}{{{n_2}}}{M_2}{V_2}$

$ = \frac{2}{{10}} \times 10 \times \frac{1}{{10}} = \frac{1}{5} = 0.2$

For (d), ${M_1}{V_1} = 0.02 \times 10 = \frac{1}{5}$

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