MCQ
A solution of $10\, ml$ $\frac{M}{{10}}FeS{O_4}$was titrated with $KMn{O_4}$ solution in acidic medium. The amount of $KMn{O_4}$ used will be
- A$5\, ml $ of $0.1\, M$
- B$10\, ml$ of $ 1.1\, M$
- C$10\, ml $ of $0.5\, M$
- ✓$10\, ml$ of $0.02\, M$
$\frac{{{M_1}{V_1}}}{{{n_1}}}$ = $\frac{{{M_2}{V_2}}}{{{n_2}}}$;
${M_1}{V_1} = \frac{{{n_1}}}{{{n_2}}}{M_2}{V_2}$
$ = \frac{2}{{10}} \times 10 \times \frac{1}{{10}} = \frac{1}{5} = 0.2$
For (d), ${M_1}{V_1} = 0.02 \times 10 = \frac{1}{5}$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

