MCQ
For the reaction $2N{O_{2(g)}}$ $\rightleftharpoons$ $2N{O_{(g)}} + {O_{2(g)}}$,${K_c} = 1.8 \times {10^{ - 6}}$ at $185\,^oC$. At $185\,^oC$ the $K_c$ for $N{O_{(g)}}$ $+$ $\frac{1}{2}{O_{2(g)}}$ $\rightleftharpoons$ $N{O_{2(g)}}$ is
  • A
    $1.95 \times {10^{ - 3}}$
  • B
    $1.95 \times {10^3}$
  • $7.5 \times {10^2}$
  • D
    $0.9 \times {10^6}$

Answer

Correct option: C.
$7.5 \times {10^2}$
(c) ${K_{{c_1}}} = \frac{{{{[NO]}^2}[{O_2}]}}{{{{[N{O_2}]}^2}}} = 1.8 \times {10^{ - 6}}$  $⇒$ ${{K}_{{{c}_{2}}}}=\frac{[N{{O}_{2}}]}{[NO]\,\,{{[{{O}_{2}}]}^{{1}/{2}\;}}}$

${K_{{c_1}}} = \frac{1}{{K_{{c_2}}^2}}$; $1.8 \times {10^{ - 6}} = \frac{1}{{{K_{{c_2}}}^2}}$ $⇒$ ${K_{{c_2}}} = 7.5 \times {10^2}$

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