A sphere carrying charge of $Q$ having weight $w$ falls under gravity between a pair of vertical plates at a distance of $d$ from each other. When a potential difference $V$ is applied between the plates the acceleration of sphere changes as shown in the figure, to along line $BC$. The value of $Q$ is :-
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$\tan 45^{\circ}=\frac{q E}{m g} \Rightarrow w=\frac{V}{d} q \Rightarrow q=\frac{w d}{V}$
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