MCQ
A spring of force constant $10 \mathrm{~N} / \mathrm{m}$ has an initial stretch $0.20 \mathrm{~m}$. In changing the stretch to $0.25 \mathrm{~m}$, the increase in potential energy is about
- ✓0.1 joule
- B0.2 joule
- C0.3 joule
- D0.5 joule
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