A steady current is set up in a cubic network composed of wires of equal resistance and length $d$ as shown in figure. What is the magnetic field at the centre P due to the cubic network
A$\frac{\mu_0}{4 \pi} \frac{2 I}{d}$
B$\frac{\mu_0}{4 \pi} \frac{2 I}{\sqrt{2} d}$
C$0$
D$\frac{\mu_0}{4 \pi} \frac{\theta \pi I}{d}$
Medium
Download our app for free and get started
C$0$
c (c)
By symmetry, the magnetic field at the centre $P$ is zero.
Download our app
and get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
Two particles of charges $+Q$ and $-Q$ are projected from the same point with a velocity $v$ in a region of uniform magnetic field $B$ such that the velocity vector makes an angle $q$ with the magnetic field. Their masses are $M$ and $2M,$ respectively. Then, they will meet again for the first time at a point whose distance from the point of projection is
Two mutually perpendicular insulated conducting wires carrying equal currents $I$, intersect at origin. Then the resultant magnetic induction at point $P(2m, 3m)$ will be
Due to the flow of current in a circular loop of radius $R$, the magnetic induction produced at the centre of the loop is $B$. The magnetic moment of the loop is $({\mu _0} = {\rm{permeability}}\,{\rm{constant)}}$
A galvanometer is used in laboratory for the null point in electrical experiments. If, on passing a current of $6 \,m A$ it produces a deflection of $2^{\circ},$ its figure of merit is close to :
A uniform conducting wire $A B C$ has a mass of $10 \,g$. A current of $2 \,A$ flows through it. The wire is kept in a uniform magnetic field $B=2 T$. The acceleration of the wire will be ............. $ms ^{-2}$
A proton and an $\alpha - $particle enter a uniform magnetic field perpendicularly with the same speed. If proton takes $25$ $\mu \, sec$ to make $5$ revolutions, then the periodic time for the $\alpha - $ particle would be........$\mu \, sec$
A negative test charge is moving near a long straight wire carrying a current. The force acting on the test charge is parallel to the direction of the current. The motion of the charge is