The magnitude of magnetic induction at mid-point $O$ due to current arrangement as shown in Fig will be
A$\frac{\mu_0 I}{2 \pi a }$
B$0$
C$\frac{\mu_0 I }{4 \pi a }$
D$\frac{\mu_0 I}{\pi a }$
JEE MAIN 2023, Medium
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D$\frac{\mu_0 I}{\pi a }$
d Magnetic field due to current in $BC$ and $ET$ are outward at point ' $O$ '
$B _0=\frac{\mu_0 i }{4 \pi r }+\frac{\mu_0 i }{4 \pi r }=\frac{\mu_0 i }{2 \pi r }=\frac{\mu_0 i }{\pi a }$
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