Due to the flow of current in a circular loop of radius $R$, the magnetic induction produced at the centre of the loop is $B$. The magnetic moment of the loop is $({\mu _0} = {\rm{permeability}}\,{\rm{constant)}}$
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(b) $B = \frac{{{\mu _0}i}}{{2R}} \Rightarrow i = \frac{{B \times 2R}}{{{\mu _0}}}$
Now, $M = i \times A = i\pi {R^2} = \frac{{B \times 2R}}{{{\mu _0}}} \times \pi {R^2} = \frac{{2\pi B{R^3}}}{{{\mu _0}}}$
Now, $M = i \times A = i\pi {R^2} = \frac{{B \times 2R}}{{{\mu _0}}} \times \pi {R^2} = \frac{{2\pi B{R^3}}}{{{\mu _0}}}$
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