
Velocity $=$ Slope of distance - Time graph
Last portion of given graph is a straight line which indicates that velocity is constant, i.e. terminal velocity is reached.
From data of graph, Terminal velocity,
$v=\frac{x_2-x_1}{t_2-t_1}=0.4-0.3$
$=\frac{0.1}{0.3}=0.33 \,m / s$
[Given: Surface tension of the liquid is $0.075 \mathrm{Nm}^{-1}$, atmospheric pressure is $10^5 \mathrm{~N} \mathrm{~m}^{-2}$, acceleration due to gravity $(g)$ is $10 \mathrm{~m} \mathrm{~s}^{-2}$, density of the liquid is $10^3 \mathrm{~kg} \mathrm{~m}^{-3}$ and contact angle of capillary surface with the liquid is zero]

