A straight conductor carrying current $i$ splits into two parts as shown in the figure. The radius of the circular loop is $R$. The total magnetic field at the centre $P$ of the loop is
  • A$0$
  • B$\frac {3 \mu_{0} i} {32 R}$, outward
  • C$\frac {3 \mu_{0} i} {32 \mathrm{R}},$ Inward
  • D$\frac{\mu_{0} \mathrm{i}}{2 \mathrm{R}},$ inward
NEET 2019, Medium
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