A submarine experiences a pressure of 5.05 10^6 ,Pa at a depth of… - Vidyadip

MCQ

A submarine experiences a pressure of $5.05\times 10^6\,Pa$ at a depth of $d_1$ in a sea. When it goes further to a depth of $d_2,$ it experiences a pressure of $8.08\times 10^6\,Pa.$ Then $d_2 -d_1$ is approximately ........ $m$ (density of water $= 10^3\,kg/m^3$ and acceleration due to gravity $= 10\,ms^{-2}$ )

A
$400$
B
$500$
C
$600$
✓
$303$

✓

Answer

Correct option: D.

$303$

d
${P_1} = 5.05 \times {10^6}\,;\,{P_2} = 8.08 \times {10^6}$

${P_2} - {P_1} = \rho g\left( {{d_2} - {d_1}} \right)$

${d_2} - {d_1} = \frac{{3.03 \times {{10}^6}}}{{{{10}^3} \times 10}} = 3.03 \times {10^2} = 303$

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