Question
A thermodynamic system undergoes cyclic process $ABCDA $ as shown in figure. The work done by the system in the cycle is
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Answer
(d) $W_{BCOB} = -$ Area of triangle $BCO = - \frac{{{P_0}{V_0}}}{2}$
$W_{AODA} = + $ Area of triangle $AOD = + \frac{{{P_0}{V_0}}}{2}$
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