A thin rod is bent in the shape of a small circle of radius $'r'$. If the charge per unit length of the rod is $'\sigma ',$ and if the circle is rotated about its axis at the rate of $'n'$ rotation per second, the magnetic induction at a point on the axis at a large distance $'y'$ from the centre is
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${{\text{B}}_y} = \frac{{{\mu _0}{\text{I}}{{\text{R}}^2}}}{{2{{\left( {{{\text{y}}^2} + {{\text{R}}^2}} \right)}^{3/2}}}} = \frac{{{\mu _0}{\text{I}}{{\text{R}}^2}}}{{2{{\text{y}}^3}}}({\text{forY}} >  >  > {\text{R}})$

$\left[\because I=\frac{q}{t}=\frac{\sigma(2 \pi R)}{t}=\sigma(2 \pi R) n\right]$

$\mathrm{B}_{\mathrm{y}}=\frac{\mu_{0} \sigma(2 \pi \mathrm{R}) \mathrm{nR}^{2}}{2 \mathrm{y}^{3}}=\frac{\mu_{0} \sigma \pi \mathrm{R}^{3} \mathrm{n}}{\mathrm{y}^{3}}$

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