A horizontal overhead power line is at a height of $4\,m$ from the ground and carries a current of $100\,A$ from east to west. The magnetic field directly below it on the ground is $(\mu _0 = 4\pi \times 10^{-7}\,TmA^{-1})$
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The magnetic field $B=\frac{\mu_{0}}{4 \pi} \frac{2 I}{r}=10^{-7} \times \frac{2 \times 100}{4}=5 \times 10^{-6} T$

According to right hand palm rule, the magnetic fleld is directed towards south.

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