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Motion in a Straight Line — Physics STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 SciencePhysicsMotion in a Straight Line3 Marks
Question
A train moves from one station to another in two hours time. Its speed during the motion is shown in the graph. Determine the maximum acceleration during the journey. Also calculate the distance covered during the time interval from $0.75h$ to $1\ hour$.
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Answer

We know that the slope of the velocity-time graph gives acceleration. Change in velocity in this interval ( 0.75 h to 1 hour) $=(60-20) \mathrm{km} / \mathrm{h}^{-1}=40 \mathrm{~km} / \mathrm{h}^{-1} $
$\therefore$ Acceleration in this interval $=\frac{40 \mathrm{~km} / \mathrm{h}^{-1}}{\frac{1}{4} \mathrm{~h}}=160 \mathrm{~km} / \mathrm{h}^{-2}$
Distance covered during the time interval from 0.75 h to $1 \mathrm{~h}=$ Area under the corresponding v - t graph $=\frac{1}{1}(20+60) 0.25=10 \mathrm{~km}$.

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