MCQ
A transition metal $M$ forms a volatile chloride which has a vapour density of $94.8$. If it contains $74.75\%$ of chlorine the formula of the metal chloride will be
  • A
    $MCl_3$
  • B
    $MCl_2$
  • $MCl_4$
  • D
    $MCl_5$

Answer

Correct option: C.
$MCl_4$
c
$74.75\%$ of chlorine means $74.75\,g$ chlorine is present in $100\,g$ of metal chloride.

Weight of metal $= 100\,g - 74.75\,g$

                          $= 25.25\,g$

Equivalent weight

$ = \frac{{weight\,of\,metal}}{{weight\,of\,chlorine\,}} \times 35.5$

$ = \frac{{25.25}}{{74.75}} \times 35.5 = 12$

Valency of metal

$ = \frac{{2 \times V.D.}}{{Equivalent\,wt.of\,metal + 35.5}}$

$ = \frac{{2 \times 94.8}}{{12 + 35.5}} = 4$

$\therefore $ Formula of compound $= MCl_4$

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