Question
A transparent solid cylindrical rod has a refractive index of $\frac{4}{\sqrt {3}}$ It is surrounded by a medium of refractive index $2$. A light ray is incident at the mid-point of one end of the rod as shown in the figure.

The incident angle $\theta $ for which the light ray grazes along the wall of the rod is

Answer

$\sin \theta=\frac{4}{\sqrt{3}} \sin r$

$\sin (90-r) \times \frac{4}{\sqrt{3}}=\sin 90 \times 2$

$\cos r=\frac{\sqrt{3}}{2}$

$r=30^{\circ}$

$\sin \theta=\frac{4}{\sqrt{3}} \sin 30^{\circ}$

$\sin \theta=\frac{2}{\sqrt{3}}$

$\theta=\sin ^{-1} \frac{2}{\sqrt{3}}$

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