A uniform chain of length $L$ which hanges partially from a table, is kept in equilibrium by friction. The maximum length that can withstand without slipping is $l$ , then coefficient of friction between the table and the chain is
A$\frac{l}{L}$
B$\frac{l}{{L + l}}$
C$\frac{l}{{L - l}}$
D$\frac{L}{{L + l}}$
Medium
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C$\frac{l}{{L - l}}$
c $\mathrm{m}_{1} \mathrm{g}=\mu \mathrm{m}_{2} \mathrm{g} \quad \mathrm{m}_{1} \rightarrow$ mass of hanged part
$\mathrm{m}_{2} \rightarrow$ mass of remaining part
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