A uniform conducting wire $ABC$ has a mass of $10\,g$. A current of $2\,A$ flows through it. The wire is kept in a uniform magnetic field $B = 2T.$ The acceleration of the wire will be
Medium
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(b) The given curved wire can be treated as a straight wire as shown
Force acting on the wire $AC$, $F = Bil = 2 \times 2 \times 3 \times {10^{ - 2}}$
= $12 \times {10^{ - 2}}\,N$ along $y-$axis.
So acceleration of wire $ = \frac{F}{m} = \frac{{12 \times {{10}^{ - 2}}}}{{10 \times {{10}^{ - 3}}}} = 12\,m/{s^2}$
Force acting on the wire $AC$, $F = Bil = 2 \times 2 \times 3 \times {10^{ - 2}}$
= $12 \times {10^{ - 2}}\,N$ along $y-$axis.
So acceleration of wire $ = \frac{F}{m} = \frac{{12 \times {{10}^{ - 2}}}}{{10 \times {{10}^{ - 3}}}} = 12\,m/{s^2}$
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