a
In triangle shape ${N}_{{t}}=\frac{24 {a}}{3 {a}}=8$
In square ${N}_{{s}}=\frac{24 {a}}{4 {a}}=6$
$\frac{{M}_{{t}}}{{M}_{3}}=\frac{{N}_{{t}} {IA}_{{t}}}{{N}_{{s}} {I}_{{s}}}[{I}$ will be same in both $]$
$=\frac{8 \times \frac{\sqrt{3}}{4} \times a^{2}}{6 \times a^{2}}$
$\frac{{M}_{{t}}}{{M}_{{s}}}=\frac{1}{\sqrt{3}}$
${y}=3$