- At O.
- At a distance less than $\frac{\text{l}}2{}$ from O.
- At a distance $\frac{\text{l}}2{}$ from O.
- At a distance larger than $\frac{\text{l}}2{}$ from O.
Explanation:
It is given that there is no force along x-axis.
COM of rod will remain and will not shift along x-axis (horizontal direction).
Force gravity is acting along y-axis (vertical direction). So, COM will shift along the y-axis by $\frac{\text{l}}2{}$ distance and COM of horizontal rod is at a distance $\frac{\text{l}}2{}$ from one end.
Therefore, lower end of the rod will remain at a distance $\frac{\text{l}}2{}$ from O.
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$\frac{\text{V}_1+\text{V}_2}{2}$
$\frac{2\text{V}_1+\text{V}_2}{\text{V}_1+\text{V}_2}$
$\frac{2\text{V}_1\text{V}_2}{\text{V}_1+\text{V}_2}$
$\frac{\text{L}(\text{V}_1+\text{V}_2)}{\text{V}_1\text{V}_2}$
They use different lengths of the pendulum and /or record time for different number of oscillations. The observations are shown in the table.
Least count for length $=0.1 \mathrm{~cm}$
Least count for time $=0.1 \mathrm{~s}$
| Student | Length of the pendulum $(cm)$ | Number of oscillations $(n)$ | Total time for $(n)$ oscillations $(s)$ | Time period $(s)$ |
| $I.$ | $64.0$ | $8$ | $128.0$ | $16.0$ |
| $II.$ | $64.0$ | $4$ | $64.0$ | $16.0$ |
| $III.$ | $20.0$ | $4$ | $36.0$ | $9.0$ |
If $\mathrm{E}_{\mathrm{I}}, \mathrm{E}_{\text {II }}$ and $\mathrm{E}_{\text {III }}$ are the percentage errors in g, i.e., $\left(\frac{\Delta \mathrm{g}}{\mathrm{g}} \times 100\right)$ for students $\mathrm{I}, \mathrm{II}$ and III, respectively,


