c
We know that force exerted by fluid coming out on the container is $\rho A v^{2}$
$\mathrm{v}=$ velocity of fluid
$v=\sqrt{2 g \frac{H}{2}}$
$A=$ area of the hole
Acceleration of the tank
$=\frac{\rho \mathrm{Av}^{2}}{\rho(\mathrm{NAH})}$
$=\frac{\rho(\mathrm{AgH})}{\rho \mathrm{NAH}}=\frac{\mathrm{g}}{\mathrm{N}}$