The magnetic field at the center of current carrying circular loop is $B _{1}$. The magnetic field at a distance of $\sqrt{3}$ times radius of the given circular loop from the center on its axis is $B_{2}$. The value of $B_{1} / B_{2}$ will be.
  • A$9: 4$
  • B$12: \sqrt{5}$
  • C$8: 1$
  • D$5: \sqrt{3}$
JEE MAIN 2022, Medium
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