A wave equation which gives the displacement along $y-$direction is given by $y = 0.001\sin (100t + x)$ where $x$ and $y$ are in meterand t is time in second. This represented a wave
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(d) Compare the given equation with
$y = a\sin (\omega t + kx)$
$y = a\sin (\omega t + kx)$
==> $\omega = 2\pi n = 100$
==> $n = \frac{{50}}{\pi }Hz$
$k = \frac{{2\pi }}{\lambda } = 1$
==> $\lambda = 2\pi $ and $v = \omega /k = 100\,m/s$
Since $‘+’$ is given between $t$ terms and $x$ term, so wave is travelling in negative $x-$direction.
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