$v _{\max }=\sqrt{\mu Rg }=\sqrt{(0.2) \times 2 \times 9.8}$

$v _{\max }=1.97\, m / s$

$7 \,km / h =1.944\, m / s$

Speed is lower than $v _{\max }$, hence it can take safe turn.

Statement $II:$

$v _{\max }=\sqrt{ Rg \left[\frac{\tan \theta+\mu}{1-\mu \tan \theta}\right]}$

$=\sqrt{2 \times 9.8\left[\frac{1+0.2}{1-0.2}\right]}=5.42 \,m / s$

$18.5 \,km / h =5.14 \,m / s$

Speed is lower than $v _{\max }$, hence it can take safe turn.