A whistle producing sound waves of frequencies $9500\ Hz$ and above is approaching a stationary person with speed $v\ ms^{-1}$. The velocity of sound in air is $300\ ms^{-1}$. If the person can hear frequencies upto a maximum of $10,000\ Hz$, the maximum value of $v$ upto which he can hear whistle is ... $ms^{-1}$
A$30$
B$15$$\sqrt 2 $
C$\frac{{15}}{{\sqrt 2 }}$
D$15$
AIEEE 2006, Medium
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D$15$
d $v^{\prime}=v\left[\frac{v}{v-v_{s}}\right] \Rightarrow 10000=9500\left[\frac{300}{300-v}\right]$
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