A heat engine is involved with exchange of heat of $1915\, J,$ $-40\, J ,+125\, J$ and $-Q\,J$, during one cycle achieving an efficiency of $50.0 \%$. The value of $Q$ is.......$J$
JEE MAIN 2020, Medium
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$\eta=\frac{\text { Work done }}{\text { Heat supplied }}$
$\frac{1}{2}=\eta=\frac{1915-40+125- Q }{1915+125}$
$\frac{1}{2}=\frac{2000- Q }{2040}$
$2040=4000-2 Q$
$2 Q =1960$
$Q =980 J$
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