A wire length $2\,m$ carrying a current of $1\,A$ is bent to form a circle. The magnetic moment of the coil is
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$l= 2 \,\mathrm{m} \quad 2 \pi \mathrm{r}=\ell$
$\mathrm{r}=\frac{\ell}{2 \pi}=\frac{2}{2 \pi}=\frac{1}{\pi}$
$\mathrm{M}=\mathrm{IA}=\mathrm{I} \pi \mathrm{r}^{2}=1 \times \pi \times \frac{1}{\pi^{2}}=\frac{1}{\pi}\, \mathrm{A}-\mathrm{m}^{2}$
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