Question
A wire of length $10cm$ translates in a direction making an angle of $60°$ with its length. The plane of motion is perpendicular to a uniform magnetic field of $1.0T$ that exists in the space. Find the emf induced between the ends of the rod if the speed of translation is $20cm/s^{-1}$.

Answer


$\text{l}=10\text{cm}=0.1\text{m};$
$\theta=60^{\circ}; \ \text{B}=1\text{T}$
$\text{V}=20\text{cm}/\text{s}=0.2\text{m}/\text{s}$
$\text{E}=\text{Bvl}\sin60^{\circ}$
[As we have to take that component of length vector which is $\perp\text{r}$ to the velocity vector]
$=1\times0.2\times0.1\times\frac{\sqrt{3}}{2}$
$=1.732\times10^{-2}=17.32\times10^{-3}\text{V}.$

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