Two cylindrical hollow drums of radii R and 2R, and of a common height h, are rotating with angular velocities $\omega$ (anti-clockwise) and $\omega$ (clockwise), respectively. Their axes, fixed are parallel and in a horizontal plane separated by $(3\text{R}+\delta).$ They are now brought in contact $(\delta\rightarrow0){:}$
  1. Show the frictional forces just after contact.
  2. Identify forces and torques external to the system just after contact.
  3. What would be the ratio of final angular velocities when friction ceases?
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  1. The frictional forces acting between two cylindrical hollow drums are as shown in the diagram below:
Force F upward shows the friction force on left drum.
Force F downward shows the friction force on right drum.
  1. $F^1 = F = F”$ where $F^1$ and $F”$ are external forces through support.
$\Rightarrow F_{net} = 0$ (one each cylinder)
Net external torque to the system about any axis = $Fx_3R$, anticlockwise,

  1. Let $R_1$ and $R_2​​​​​​​$ be final angular velocities of smaller and bigger drum respectively (anti­clockwise and clockwise respectively).
Finally, there will be no friction. When friction ceases at the point of contact, then both drums has equal linear velocity at that point.
$^vA = ^vB$
Hence, $R_1 = 2R_2$
Important point: Friction force just opposes the relative motion of point of contacts at any instant. So, we should be very careful while indicating direction of frictional forces.
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