A wire of length $L$ metre carrying a current of $I$ ampere is bent in the form of circle. Its magnetic moment is
NEET 2020, Medium
Download our app for free and get startedPlay store
Length of wire, $L =2 \pi R$

Radius of loop, $R=\frac{L}{2 \pi}$

Magnetic moment, $M =I A$

$=I\left(\frac{\pi L^{2}}{4 \pi^{2}}\right)$

$=\frac{I L^{2}}{4 \pi} A \;m^{2}$

art

Download our app
and get started for free

Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*

Similar Questions

  • 1
    In a toroid the number of turns per unit length is $1000$ and current through it is $\frac{1}{4 \pi}$ ampere. The magnetic field produced inside (in $weber / m ^2$ ) will be
    View Solution
  • 2
    A straight wire of diameter $0.5\, mm$ carrying a current of $1\, A$ is replaced by another wire of $1\, mm$ diameter carrying the same current. The strength of magnetic field far away is
    View Solution
  • 3
    On connecting a battery to the two corners of a diagonal of a square conductor frame of side $a$ the magnitude of the magnetic field at the centre will be
    View Solution
  • 4
    In the figure, shown the magnetic induction at the centre of there $arc$ due to the current in portion $AB$ will be
    View Solution
  • 5
    A moving charge will gain energy due to the application of
    View Solution
  • 6
    Biot-Savart, law indicates that the moving electrons (velocity $v$) produce a magnetic  field $B$ such that
    View Solution
  • 7
    An electron moves in a circular orbit with a uniform speed $v$. It produces a magnetic field $B$ at the centre of the circle. The radius of the circle is proportional to
    View Solution
  • 8
    A wire of length $314\,cm$ carrying current of $14\,A$ is bent to form a circle. The magnetic moment of the coil is $........A- m ^{2}$. [Given $\left.\pi=3.14\right]$
    View Solution
  • 9
    In the diagram, $I_1$ , $I_2$ are the strength of the currents in the loop and infinite long straight conductor respectively. $OA = AB = R$ . The net magnetic field at the centre $O$ is zero. Then the ratio of the currents in the loop and the straight conductor is 
    View Solution
  • 10
    A galvanometer of resistance $40\,\Omega $ gives a deflection of $5\, divisions$ per $mA$. There are $50\, divisions$ on the scale. The maximum current that can pass through it when a shunt resistance of $2\,\Omega $ is connected is ................ $mA$
    View Solution