The mass and length of a wire are $M$ and $L$ respectively. The density of the material of the wire is $d$. On applying the force $F$ on the wire, the increase in length is $l$, then the Young's modulus of the material of the wire will be
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(d) $Y = \frac{F}{A}\frac{L}{l}$ $ = \frac{{Fd{L^2}}}{{Ml}}$
As $M =$ volume $\times$ density $ = A \times L \times d$ $\therefore$ $A = \frac{M}{{Ld}}$
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