For pulley

\(F=2 T\)

for block

\(T=10 \,g =100 \,N\)

\(F=200 \,N\)

For horizontal equilibrium

\(T_1 \cos 60^{\circ}=T_2 \cos 30^{\circ}\)

\(T_1=2 T_2 \frac{\sqrt{3}}{2}=\sqrt{3} T_2 \ldots(i)\)

For vertical equilibrium

\(T_1=\sin 60^{\circ}+T_2 \sin 30^{\circ}=200\)

Using \((i)\) and \((ii)\) solve for \(T_2 \ldots(ii)\)

\(2 T_2=200\)

\(T_2=100 \,N\)